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For example if a coin is flipped 3 times i know how to calculate all the possible outcomes Assume it's fair, the probability of getting 600 or more. I don't understand how i reduce that count to only the combinations where the order.

1 there are two possibilities for each of the five tosses of the coin, so there are $2^5 = 32$ possible outcomes in your sample space, as you found If a coin is flipped 1000 times, 600 are heads, would you say it's fair What is the probability that heads.

A participant is allowed to ask 1 yes or no question (e.g

Was the first coin flip heads?), then plays a game where he tries to guess all 100 coins A sees a tail on coin flip 2 and 4 so he picks 3, b does the same After running this on a computer simulation i get a 60% winrate Although i don't fully understand why

I understand the formulae for combinations and permutations and that for the binomial distribution However, i'm confused about their application to coin tossing A classical example that's given for probability exercises is coin flipping Generally it is accepted that there are two possible outcomes which are heads or tails

If you get heads you win \\$2 if you get tails you lose \\$1

What is the expected value if you flip the coin 1000 times I know that the expected value of flipping the coin once i. Flip coin until more heads ask question asked 1 year, 11 months ago modified 1 year, 11 months ago

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